write the expression for Lorentz magnetic force on a particle of charge q moving with velocity V in a magnetic field b show that no work is done by this force on the charged particle?
Answers
Answered by
27
lorentz force = mangetic force + electric
force
F= [qvb sinϴ +qe]
Solution :
F→=q(V→×B→)F→=q(V→×B→)
(i) F→F→ is perpendicular to both V→V→ and B→B→ .
If ds→ds→ is the instantaneous displacement of the change ds→ds→ is also perpendicular to F→F→
Work done by this force = increase in kinetic energy
w=F→.ds→w=F→.ds→
=Fscos90∘=Fscos90∘
But cos90∘=0cos90∘=0
w=0w=0
Hence increase in kinetic energy is zero.
but electric force not zero
force
F= [qvb sinϴ +qe]
Solution :
F→=q(V→×B→)F→=q(V→×B→)
(i) F→F→ is perpendicular to both V→V→ and B→B→ .
If ds→ds→ is the instantaneous displacement of the change ds→ds→ is also perpendicular to F→F→
Work done by this force = increase in kinetic energy
w=F→.ds→w=F→.ds→
=Fscos90∘=Fscos90∘
But cos90∘=0cos90∘=0
w=0w=0
Hence increase in kinetic energy is zero.
but electric force not zero
Answered by
6
Answer:
lorentz force = mangetic force + electric
force
F= [qvb sinϴ +qe]
Solution :
F→=q(V→×B→)F→=q(V→×B→)
(i) F→F→ is perpendicular to both V→V→ and B→B→ .
If ds→ds→ is the instantaneous displacement of the change ds→ds→ is also perpendicular to F→F→
Work done by this force = increase in kinetic energy
w=F→.ds→w=F→.ds→
=Fscos90∘=Fscos90∘
But cos90∘=0cos90∘=0
w=0w=0
Hence increase in kinetic energy is zero.
but electric force not zero
Read more on Brainly.in - https://brainly.in/question/4255816#readmore
Similar questions