Question

write the expression for the equilibrium constant kc for the following equilibrium 3Fe(s)+4h2o that is fe3o4(s)+4h2(g)​

Answer 1

Answer:

The relationship between Kp and Kc is as follows:

Kp=Kc(RT)Δn

When Δn=0, the term (RT)Δn becomes (RT)0=1

Hence, Kp=Kc

This is true for the reaction 3Fe(s)+4H2O(g)⇔Fe3O4(s)+4H2(g) for which Δn=4−4=0 

Here, only the number of moles of gaseous substances are considered.