Write the expression for the equilibrium reaction 4NH3 +5O2--4NO+6H2O. What happens to the value of ke when the above reaction is reversed
Answers
Answer:Concept of Equilibrium
• As a system approaches
equilibrium, both the
forward and reverse
reactions are occurring.
• At equilibrium, the
forward and reverse
reactions are proceeding
at the same rate. • Once equilibrium is
achieved, the amount of
each reactant and
product remains
constant.
Explanation:The Equilibrium Constant
• Consider the generalized reaction
The equilibrium expression for this
reaction would be
Kc =
[C]c
[D]d
[A]a
[B]b
aA + bB cC + dD
Since pressure is proportional to
concentration for gases in a closed
system, the equilibrium expression can
also be written
Kp
=
(PC
)c
(PD
)d
(PA
)a
(PB
)b
Chemical equilibrium occurs when
opposing reactions are proceeding at equal rates.
Since, in a system at equilibrium, both the forward
and reverse reactions are being carried out, we
write its equation with a double arrow.
Forward reaction:
N2O4 (g) 2 NO2 (g)
Rate Law:
Rate = kf [N2O4
]
N2O4 (g) 2 NO2 (g)
Reverse reaction:
2 NO2 (g) N2O4 (g)
Rate Law:
Rate = kr [NO2
]2
4
Equilibrium Constant
• Therefore, at equilibrium
Ratef = Rater
kf [N2O4
] = kr [NO2
]2
• Rewriting this, it becomes
kf
kr
[NO2
]2
[N2O4
] =
Keq
=
kf
kr
[NO2
]2
[N2O4
]
= = a constant
Hope this helps!!!
Answer:
answer in attachment.
