Question

write the expression for the path(trajectory)of the projectile and explain the terms​

Answer 1

Answer:

Derive an expression for path of projectile

Trajectory of a projectile is a parabolic trajectory. This explanation and the equation are very useful to class 11 students and IIT JEE aspirants. During the derivation we found, if a projectile is thrown with sped 'u' and at an angle θ with the horizontal, y = x tanθ / ( 2 u^2 cosθ^2).

Explanation:

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Answer 2

• As we know that trajectory is the path, by neglecting all other forces particle will take under the action of gravity.

• The forces such as friction from air resistance.

• It is also known as a flight path.

• The object can be moved under the gravity action.

• We can express trajectory as,

                 $y=x tan Ф$Ф- $\frac{gx2}{2v2cos2}$Ф

• Where;

          Y= horizontal component.

          x= Vertical component.

         Ф= Angle of projection.

         g= Acceleration.

         v= Absolute initial velocity.