Question

Write the expression for the radii of orbits of hydrogen atom calculate the radius of smallest orbit

Answer 1

Answer:

the radius of the second bohr orbit of the hydrogen atom is r=2.116*10^-10 m. The orbital speed can be found using v = SQRT(G*M/R). The R value (radius of orbit) is the earth's radius plus the height above the earth - in this case, 6.59 x 106

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Answer 2

Answer:The formula is r=a°n^2/Z

Where 'r' is radius,n is principle quantum no.,a° =52.9pm & Z is atomic no.

Explanation: Calculation of radius of smallest orbit i.e Bohr's orbit

Since r=a°n^2/Z

And for smallest orbit of Hydrogen

n=1& Z=1

So, r= a°= 52.9pm

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