Question

write the Expression in reversible is theremal free expansion of ideal gas​

Answer 1

Answer:

For isothermal reversible and irreversible changes; equation 1 can be expressed as: Isothermal reversible change: q = -w = pex(Vf-Vi) Isothermal reversible change: q = -w = nRTln (Vf/Vi) = 2.303 nRT log (Vf/Vi) Adiabatic change: q =0, ∆U = w.

Answer 2

Answer:

Since the First Law of Thermodynamics states that ΔU = Q + W (IUPAC convention), it follows that Q = −W for the isothermal compression or expansion of ideal gases.