Question

Write the expression of 16 x² y² - 1​

Answer 1

= 16x²y²-1

= (16x²y²)-(1)²

= (4xy)²-(1)²

= Using: (a)²-(b)²=(a+b)(a-b)

= (4xy+1)(4xy-1)

Answer 2

$\large{\underline{\underline{\bold{\red{\sf{Bonjour !}}}}}}$

$16 {x}^{2} {y}^{2} - 1 \\ {(4xy)}^{2} - 1$

${(4xy)}^{2} - {1}^{2} \\ (4xy - 1)(4xy + 1)$

$\large{\bold{\blue{\sf{Thanks}}}}$