Write the expression using exponents.
66 · 66 · 66 = i have to type this answer in plzz hurry
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Suppose a __ ___Ra nucleus at rest and in ground state undergoes __-decay to a __ ___Rn nucleus in its excited state. The kinetic energy of the emitted __ particle is found to be 4.44 MeV. __ ___Rn nucleus then goes to its ground state by __-decay. The energy of the emitted __ photon is _____keV.
[Given: atomic mass of __ ___Ra =226.005 u,atomic mass of __ ___Rn = 222.000 u , atomic mass of __ particle= 4.000 u, 1 u = 931 MeV/c_, c is speed of the light]
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this can written as (66)^3
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