Question

write the extended form of( x+y cube) and using this indentifier find (102)cube​

Answer 1

Answer:

(x+y)^3 = x ^3+ y^3 + 3x^2y + 3xy^2

(100 +2 )^3

1000000 + 8 + 60000+ 1200

Answer 2

1061208

Let us rewrite (102)3 as (100+2)3

Now using the identity (a+b)3=a3+b3+3ab(a+b),

we get(100+2)3=1003+23+[(3×100×2)(100+2)]=1000000+8+(600×102)=1000000+8+61200=1061208

Hence, (102)3=1061208

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