Question

Write the factors of:
(2x-3y)^3+(3y-4z)^3+(4z-2x)^3

Answer 1

solution :

*************************************
We know that ,

If a + b + c = 0 ,then

a³ + b³ + c³ = 3abc

*************************************

Here ,

a = 2x - 3y ,

b = 3y - 4z ,

c = 4z - 2x ,

Now ,

a + b + c = 2x-3y+3y-4z+4z-2x = 0

Therefore ,

(2x-3y)³+(3y-4z)³+(4z-2x)³

= 3abc

= 3(2x-3y)(3y-4z)(4z-2x)

•••••

Answer 2

Hi!

First multiply 3 with the binomial terms as stated in the question.

Then, after multiplying you will get,

=(6x-9y)+(9y-12z)+(12z-3x)

Removing the brackets ,

=6x-9y+9y-12z+12z-3x

Now , accordingly they will get cut,

=0