write the factors of the following terms i) 9p³qr² ii) -6a³bc² iii) 16abc vi) 15g³h²k^5 v) -81xyz³
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Step-by-step explanation:
- The 3 factors of 9 are:
1, 3, 9
The factor pairs of 9 are:
1 × 9 = 9
3 × 3 = 9.
- The 8 factors of -6 are:
- 1, 2, 3, 6
- -1, -2, -3, -6
- The factor pairs of -6 are:
- 1 × -6 = -6
- 2 × -3 = -6
- 3 × -2 = -6
- 6 × -1 = -6.
- The 5 factors of 16 are:
- 1, 2, 4, 8, 16
- The factor pairs of 16 are:
- 1 × 16 = 16
- 2 × 8 = 16
- 4 × 4 = 16.
- The 4 factors of 15 are:
- 1, 3, 5, 15
- The factor pairs of 15 are:
- 1 × 15 = 15
- 3 × 5 = 15.
- The 10 factors of -81 are:
- 1, 3, 9, 27, 81
- -1, -3, -9, -27, -81
- The factor pairs of -81 are:
- 1 × -81 = -81
- 3 × -27 = -81
- 9 × -9 = -81
- 27 × -3 = -81
- 81 × -1 = -81.
Answered by
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The 3 factors of 9 are:
1, 3, 9
The factor pairs of 9 are:
1 × 9 = 9
3 × 3 = 9.
The 8 factors of -6 are:
1, 2, 3, 6
-1, -2, -3, -6
The factor pairs of -6 are:
1 × -6 = -6
2 × -3 = -6
3 × -2 = -6
6 × -1 = -6.
The 5 factors of 16 are:
1, 2, 4, 8, 16
The factor pairs of 16 are:
1 × 16 = 16
2 × 8 = 16
4 × 4 = 16.
The 4 factors of 15 are:
1, 3, 5, 15
The factor pairs of 15 are:
1 × 15 = 15
3 × 5 = 15.
The 10 factors of -81 are:
1, 3, 9, 27, 81
-1, -3, -9, -27, -81
The factor pairs of -81 are:
1 × -81 = -81
3 × -27 = -81
9 × -9 = -81
27 × -3 = -81
81 × -1 = -81.
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