Math, asked by satishkumarkurrey52, 6 months ago

write the factors of the following terms i) 9p³qr² ii) -6a³bc² iii) 16abc vi) 15g³h²k^5 v) -81xyz³​

Answers

Answered by mohamedshaheedh2712
1

Answer:

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Step-by-step explanation:

  • The 3 factors of 9 are:

1, 3, 9

The factor pairs of 9 are:

1 × 9 = 9

3 × 3 = 9.

  • The 8 factors of -6 are:
  • 1, 2, 3, 6
  • -1, -2, -3, -6
  • The factor pairs of -6 are:
  • 1 × -6 = -6
  • 2 × -3 = -6
  • 3 × -2 = -6
  • 6 × -1 = -6.

  • The 5 factors of 16 are:
  • 1, 2, 4, 8, 16
  • The factor pairs of 16 are:
  • 1 × 16 = 16
  • 2 × 8 = 16
  • 4 × 4 = 16.

  • The 4 factors of 15 are:
  • 1, 3, 5, 15
  • The factor pairs of 15 are:
  • 1 × 15 = 15
  • 3 × 5 = 15.

  • The 10 factors of -81 are:
  • 1, 3, 9, 27, 81
  • -1, -3, -9, -27, -81
  • The factor pairs of -81 are:
  • 1 × -81 = -81
  • 3 × -27 = -81
  • 9 × -9 = -81
  • 27 × -3 = -81
  • 81 × -1 = -81.

Answered by pv057966
2

The 3 factors of 9 are:

1, 3, 9

The factor pairs of 9 are:

1 × 9 = 9

3 × 3 = 9.

The 8 factors of -6 are:

1, 2, 3, 6

-1, -2, -3, -6

The factor pairs of -6 are:

1 × -6 = -6

2 × -3 = -6

3 × -2 = -6

6 × -1 = -6.

The 5 factors of 16 are:

1, 2, 4, 8, 16

The factor pairs of 16 are:

1 × 16 = 16

2 × 8 = 16

4 × 4 = 16.

The 4 factors of 15 are:

1, 3, 5, 15

The factor pairs of 15 are:

1 × 15 = 15

3 × 5 = 15.

The 10 factors of -81 are:

1, 3, 9, 27, 81

-1, -3, -9, -27, -81

The factor pairs of -81 are:

1 × -81 = -81

3 × -27 = -81

9 × -9 = -81

27 × -3 = -81

81 × -1 = -81.

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