Write the factors of the polynomial 4x² +y ² + 4 + 4xy+ 8x + 4y
Answers
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Step-by-step explanation:
The value of x
2
+4y
2 +4y−4xy−2x−8 is
=x
2
+4y
2
−4xy+4y−2x−8
=(x−2y)
2
+2(2y−x)−8
=(x−2y)
2
−2(x−2y)−8
Let A=x−2y
Thus A
2
−2A−8
=(A−4)(A+2)
Re-substitute the value of A
Thus x
2
+4y
2
+4y−4xy−2x−8=(x−2y−4)(x−2y+2)
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