Question

write the family of quadratic polynomial having -1/4 and 1 as its zeros​

Answer 1

Answer:

${x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

${x}^{2} - ( \frac{ - 1}{4} + 1)x + ( \frac{ - 1}{4} \times 1) = 0$

${x}^{2} - \frac{3}{4} x - \frac{1}{4} = 0$

Please mark it as brainliest :-)

Answer 2

Answer:

sum of zeroes is -1/4+1= -1+4/4=3/4

product of zeroes is -1/4×1= -1/4

using quadratic polynomial formula

= k[x^2-(a+b)x+ab]

=k[x^2-(3/4)x+(-1/4)]

= if K=4

then,

4x^2+3x-1 is required answer