write the first 3 terms of each of the arithematic sequences described below:
1)First term 30;the sum of the first 3 terms is 300
2)First term 30;the sum of the first 4 terms is 300
3)First term 30;the sum of the first 5 terms is 300
4)First term 30;the sum of the first 6 terms is 300
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Step-by-step explanation:
1) a = 30 , S3 = 300 then T1,t2,t3
t1 = 30 , T2 = a+(n-1)d
t2 = 30 + (2-1)d
t2 = 30 +d
so, t3 = 30 + 2d
now, sn = n/2(2a +(n-1)d)
300= 3/2(2(30) +(3-1)d)
300×2/3 = 60+2d
200 = 60 + 2d
d = 70..
T1 = 30+70 = 100
t2 = 30+2(70) = 30+140 = 170..
use this method for remaining 3 sums but take the sn value as given in the question ..like
s4 = 300 then n = 4 ..
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