Math, asked by khemkatejesh, 8 months ago

write the first 6 terms of an ap in which a=7 1/2,d=1 1/2​

Answers

Answered by amiteshkumar71
0

Answer:

Second term - First term

=

−2−

(3)=

−5

Third term - Second term

=

−7−

(−2)=

−5

So, the given sequence is an A.P. with a common difference of −5.

Since each term of an A.P. is obtained by adding common difference to the preceding term.

a

5

a

4

(−5)= −12+ (−5)= −17

a

6

a

5

(−5)= −17+ (−5)= −22

and,

a

7

a

6

(−5)=

−22+

(−5)=

−27

Step-by-step explanation:

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0

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