Question

write the first five teams of the sequences whose nth team is
$an = \frac{n}{n + 1}$

please help...​

Answer 1

$<font color = gold>$

an=nn+1

Substituting n = 1, 2, 3, 4, 5, we obtain

a1=11+1=12,a2=22+1=23,a3=33+1=34,a4=44+1=45,a5=55+1=56

Therefore, the required terms are

12,23,34,45,and56

Answer 2

Answer:

$a1 = \frac{1}{1 + 1} = \frac{1}{2}$

$a2 = \frac{2}{2 + 1} = \frac{2}{3}$

$a3 = \frac{3}{3 + 1} = \frac{3}{4}$

$a4 = \frac{4}{4 + 1} = \frac{4}{5}$

$a5 = \frac{5}{5 + 1} = \frac{5}{6}$

Therefore, the required teams are 1/2, 2/3 ,3/4 ,4/5 and 5/6