Question

write the first five terms of each of the sequences are 1 to 6whose nth term are an=n(n+2)

Answer 1

3, 8, 15, 24,35

Given:

an = n(n + 2)

To Find:

First Five terms of the sequence an = n(n + 2)

Calculating:

Putting the value of n as 1 in the given equation:

a1 = 1(1 + 2)

a1 = (1)(3)

a1 = 3

First term of the sequence is 3.

Putting the value of n as 2 in the given equation:

a2 = 2(2 + 2)

a2 = 2(4)

a2 = 8

Second term of the sequence is 8.

Putting the value of n as 3 in the given equation:

a3 = 3(3 + 2)

a3 = 3(5)

a3 = 15

Third term of the sequence is 15.

Putting the value of n as 4 in the given equation:

a4 = 4(4 + 2)

a4 = 4(6)

a4 = 24

Fourth term of the sequence is 24.

Putting the value of n as 5 in the given equation:

a5 = 5(5 + 2)

a5 = 5(7)

a5 = 35

Fifth term of the sequence is 35.

Therefore, the first five terms of the sequence are 3, 8, 15, 24,35.