Question

write the first five terms of each of the sequences, whose nth terms are: 1) an= (-1)n (2n+1)/6 2) an=1/n+(-1)n​

Answer 1

Answer:

Step-by-step explanation:

1) an= (-1)n (2n+1)/6

Substitute n=1

a1= (-1)^1 (2*1+1)/6

a1=(-1) x 3/6

a1= -1*1/2

a1= -1/2

Follow the same process by substitution n=2,3,4,5 to get 2nd,3rd,4th,5th terms.

Note: (-1)n =+1 if n is even;

(-1)n =-1 if n is odd

If any doubt, feel free to ask.