Question

write the first five terms of each sequences. (i)an=n (n+2)(ii)an=n/n+1 (iii) an=2n (iv) an=2n-3/6

Answer 1

1) an = n(n + 2)

a1 = 1(1 + 2) = 3
a2 = 2(2 + 2) = 8
a3 = 3( 3 + 2) = 15
a4 = 4(4 + 2) = 24
a5 = 5(5 + 2) = 35

2) an = n / n +1

a1 = 1 / 1+1 = 1/2
a2 = 2 / 2+1= 2 / 3
a3 = 3 / 3 + 1 = 3/4
a4 = 4 / 4 + 1= 4/5
a5 = 5 / 5+1 = 5/6

3) an = 2n

a1 = 2×1 = 2
a2 = 2×2 = 4
a3 = 2 × 3= 6
a4 = 2 × 4 = 8
a5 = 2 × 5 = 10

4) an = 2n -3 / 6

a1 = 2×1 - 3 / 6 = -1/6

a2 = 2×2 - 3/ 6 = 1/6

a3 = 2×3 -3 / 6 = 3/6

a4 = 2×4 -3/ 6 = 5/6

a5 = 2×5 - 3/ 6 = 7/6


Thanks