Math, asked by Mister360, 2 months ago

Write the first five terms of
 \sf a_n = (2n – 3)/6

Answers

Answered by kailashmannem
53

 \huge{\bf{\green{\mathfrak{Question:-}}}}

  •  \textsf{Write the first five terms of :-}

  •  \sf a_n =  \sf \dfrac{2n \: - \: 3}{6}

 \huge {\bf{\orange{\mathfrak{Answer:-}}}}

  •  \textsf{The first five terms in the A.P will be,}

  •  \sf a_1 ,  \sf a_2 ,  \sf a_3 ,  \sf a_4 ,  \sf a_5

  •  \textsf{This means that n = 1,2,3,4,5 will be for the first five terms respectively.}

  •  \textsf{First term of A.P,}

  •  \textsf{Substituting n = 1,}

  •  \sf \dag \:\:\:\:\dfrac{2 \: * \: 1 \: - \: 3}{6} \: = \: \dfrac{- \: 1}{6}

  •  \textsf{Second term of A.P,}

  •  \textsf{Substituting n = 2,}

  •  \sf \dag \:\: \:\:\dfrac{2 \: * \: 2 \: - \: 3}{6} \: = \: \dfrac{1}{6}

  •  \textsf{Third term of A.P,}

  •  \textsf{Substituting n = 3,}

  •  \sf \dag \:\:\:\:\dfrac{2 \: * \: 3 \: - \: 3}{6} \: = \: \dfrac{3}{6} \: = \: \dfrac{1}{2}

  •  \textsf{Fourth term of A.P,}

  •  \textsf{Substituting n = 4,}

  •  \sf \dag \:\:\:\:\dfrac{2 \: * \: 4 \: - \: 3}{6} \: = \: \dfrac{5}{6}

  •  \textsf{Fifth term of A.P,}

  •  \textsf{Substituting n = 5,}

  •  \sf \dag \:\:\:\:\dfrac{2 \: * \: 5 \: - \: 3}{6} \: = \: \dfrac{7}{6}

 \huge{\bf{\red{\mathfrak{Conclusion:-}}}}

  •  \therefore{\sf a_{1} \: = \: \dfrac{- \: 1}{6}}

  •  \therefore{\sf a_{2} \: = \: \dfrac{1}{6}}

  •  \therefore{\sf a_{3} \: = \: \dfrac{1}{2} \: or \: \dfrac{3}{6}}

  •  \therefore{\sf a_{4} \: = \: \dfrac{5}{6}}

  •  \therefore{\sf a_{5} \: = \: \dfrac{7}{6}}

  •  \boxed{\therefore{\sf A.P \: = \: \dfrac{- \: 1}{6} \: , \: \dfrac{1}{6} \: , \: \dfrac{3}{6} \: , \: \dfrac{5}{6} \: , \: \dfrac{7}{6}.}}

Answered by SƬᏗᏒᏇᏗƦƦᎥᎧƦ
61

Required answer:-

Question:

•Write  \: the  \: first \:  five \:  terms  \: of : a_{n} = (2n - 3)/6 \\

Solution:

Given,

•a_{n} = (2n - 3)/6

To find:

• first five terms of (2n -3)/6

Assumptions:

• Taking n as 1 , 2 , 3 , 4 , 5 , 6

Step by step explaination:

First term

✎Putting value...

a_{1} =  \frac{2 \times 1 - 3}{6}   =  \frac{ - 1}{6}  \\

Second term

✎Putting value...

a_{2} =  \frac{2 \times 2 - 3}{6}  =  \frac{1}{6}  \\

Third term

Putting value...

a_{3} =  \frac{2 \times 3 - 3}{6}  =  \frac{1}{2}  \\

Fourth term

Putting value....

a_{4} =  \frac{2 \times 4 - 3}{6}  =  \frac{5}{6}  \\

Fifth term

Putting value.....

a_{5}= \frac{2 \times 5 - 3}{6}  =  \frac{7}{6}  \\

_________________________________________

Thus, the first five terms are :

 \frac{ - 1}{6} ,  \: \frac{1}{6} , \:  \frac{1}{2}, \:  \frac{5}{6} , \:  \frac{7}{6}  \\

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