Question

write the first five terms of the AP when a = - 1 d= - 4​

Answer 1

Answer:

✳a₁ = -1

✳a₂ = -5

✳a₃ = -9

✳a₄ = -13

✳ a₅ = -17

 SOLUTION  

First Term (a) = -1

Common Difference = -4

We know that ,

$\red\bigstar \boxed{\tt a(n) = a + (n-1)d}$

First Term a₁ ,

a₁ =  -1 +(1-1) -4

$\implies$

a₁ = -1

Second Term a₂ ,

a₂ = -1 + (2 - 1) -4

$\implies$

a₂ = -1 + -4

$\implies$

a₂ = -5

Third Term a₃ ,

a₃ = -1 + (3-1) -4

$\implies$

a₃ = - 1 + -8

$\implies$

a₃ = -9

Fourth Term a₄ ,

a₄ = -1 + (4-1) -4

$\implies$

a₄ = -1 + -12

$\implies$

a₄ = -13

Fifth Term a₅ ,

a₅ = -1 + (5-1) -4

$\implies$

a₅ = -1 + -16

$\implies$

a₅ = -17