Question

write the first four term of an ap whose first term and common difference is given a=10, d=4​

Answer 1

Given,

First term of the AP (a) = 10

Common difference (d) = 4

To find,

First four terms of this AP series.

Solution,

We can easily solve this mathematical problem by using the following mathematical process.

We have to keep in mind that we can get the immediate next term of an AP, if we add common difference with the previous term.

Eg. if "x" is the first term and common difference is 1 then, the second term = x+1 , third term = x+1+1 = x+2 so on.

Similarly,

First term = 10

Second term = 10+4 = 14

Third term = 14+4 = 18

Fourth term = 18+4 = 22

Hence,the first four terms are 10,14,18,22

Answer 2

SOLUTION

GIVEN

In an AP first term and common difference is given a = 10 , d = 4

TO DETERMINE

The first four term of the AP

CONCEPT TO BE IMPLEMENTED

If in an Arithmetic progression (AP)

First term = a

Common Difference = d

Then nth term of the AP

$= \sf{t_n = a + (n - 1)d}$

EVALUATION

Here it is given that, in an AP first term and common difference is given a = 10 , d = 4

We have to determine first four terms

First term = a = 10

Second Term

$= \sf{t_2 }$

$= \sf{a + (2 - 1)d}$

$\sf{ = a + d}$

$= \sf{10 + 4}$

$= 14$

Third term

$= \sf{t_3 }$

$= \sf{a + 2d}$

$\sf{ = 10 + (2 \times 4)}$

$= 10 + 8$

$= 18$

Fourth term

$= \sf{t_4 }$

$= \sf{a + 3d}$

$= 10 + (3 \times 4)$

$= 10 + 12$

$= 22$

FINAL ANSWER

The first four terms of the AP are

10 , 14 , 18 , 22

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