Question

write the first four term of an AP whose first term is 6 and common difference is -3​

Answer 1

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cm

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cm

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cmTo Find :-

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cmTo Find :-Curved surface area ( CSA )

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cmTo Find :-Curved surface area ( CSA )Solution :-

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cmTo Find :-Curved surface area ( CSA )Solution :-Curved surface area of cylinder = 2πrh

The radius of a cylinder is 12 m and height is 21 m. Find the curved surface area of the cylinder.Answer :-Given :-r = 12 cmh = 21 cmTo Find :-Curved surface area ( CSA )Solution :-Curved surface area of cylinder = 2πrhSubstituting the values in formula :-

.

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2×

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 ×

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2 1

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2 1→ \sf CSA = 2 \times 22 \times 3 \times 12CSA=2×22×3×12

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2 1→ \sf CSA = 2 \times 22 \times 3 \times 12CSA=2×22×3×12→ \sf CSA = 1584 CSA=1584

→ \sf CSA = 2 \times \frac{22}{\cancel7} \times \cancel21CSA=2× 7 22 × 2 1→ \sf CSA = 2 \times 22 \times 3 \times 12CSA=2×22×3×12→ \sf CSA = 1584 CSA=1584Curved surface area = 1584 m²

Answer 2

Answer:

9 , 6 , 3 , 0

Step-by-step explanation:

Let first four term be

a-d , a , a+d , a+2d

a=6

d=-3

a-d = 6-(-3) = 6+3= 9

a = 6

a+d = 6+(-3) = 6-3 = 3

a+2d = 6 + 2 x -3 = 6-6 = 0

therefore A.P

9 , 6 , 3 , 0