Question

Write the first four terms of an A.P.Whose first term is 3x+y and common difference is x-y..

Answer 1

first term=3x+y
second term=3x+y+x-y=4x
third term=3x+y+2(x-y)=5x-y
fourth term=3x+y+3(x-y)=6x-2y..

Answer 2

Answer:

$First\:terms \: of \:A.P:\\</p><p>3x+y,4x,(5x-y)\:and\:(6x-2y)$

Step-by-step explanation:

$Given,\: In \: A.P\\First\:term(a)=3x+y,\\common\: difference (d)=x-y$

$Second\:term(a_{2})\\=a+d\\=3x+y+x-y\\=4x$

$Third\:term(a_{3})\\=a_{2}+d\\=4x+x-y\\=5x-y$

$Fourth\:term(a_{4})\\=a_{3}+d\\=5x-y+x-y\\=6x-2y$

Therefore,

$First\:terms \: of \:A.P:\\</p><p>3x+y,4x,(5x-y)\:and\:(6x-2y)$

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