Question

Write the first four terms of an ap whose first term is -1 and common difference is 1/2

Answer 1

Answer:-1, -1/2, 0, 1/2

Step-by-step explanation:

Here, first term (a) = -1

Common difference (d) = 1/2

t1 = a = -1

t2 = t1 + d

t2 = (-1) + (1/2)

t2 = -1 + 1/2

t2 = 2(-1) + 1/2

t2 = -2 + 1/2

t2 = -1/2

t3 = t2 + d

t3 = -1/2 + 1/2

t3 = -1 + 1/2

t3 = 0/2

t3 = 0

t4 = t3 + d

t4 = 0 + 1/2

t4 = 1/2

Answer 2

Answer:

(-1,  $\frac{-1}{2\\}$  , 0 , $\frac{1}{2}$)

Step-by-step explanation:

Since the number is in AP we will use following formula

$a_{n}=a_{1}+(n-1)d$

$a_n$ = the nᵗʰ term in the sequence

$a_1$ = the first term in the sequence

d = the common difference between terms

First term is = -1 (given)

Second Term,

$a_{2}=a_{1}+(2-1)\frac{1}{2}$

$a_{2}=-1+(2-1)\frac{1}{2}$

$a_{2}=\frac{-1}{2}$

Third Term,

$a_{3}=a_{1}+(3-1)\frac{1}{2}$

$a_{3}=-1+(3-1)\frac{1}{2}$

$a_{3}=0$

Fourth Term,

$a_{4}=a_{1}+(4-1)\frac{1}{2}$

$a_{4}=-1+(4-1)\frac{1}{2}$

$a_{4}=\frac{1}{2}$

Please mark me brainlist