Question

write the first four terms of AP given value,d=-1,d=1/2

Answer 1

For the value of d=1,
a1=a
a2=a+d=a+1
a3=a+2d=a+2
a4=a+3d=a+3
AP = a , a+1 , a+2 , a+3

For the value of d=1/2,
a1=a
a2=a+d=a+1/2
a3=a+2d=a+1
a4=a+3d=a+3/2
AP = a , a+1/2 , a+1 , a+3/4.

Hope it helps...