write the first four terms of the sequence whose n terms is an=2n*2-3n+1
siddharth355:
2n power 2
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sequence will be 0,3,6,9.....
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Given,
An=2n^2-3n+1
Let ,n=1
A(1)=2*1^2-3*1+1=0,
Similarly, put n=2
A(2)=3
A(3)=6 [put n=3]
A(4)=9[put n=4]
Thus ,first four required terms of the given AP is 0,3,6,9
Hope it helps you......
:)
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