Question

write the first six terms of A.P in which
a=7 1/2, d=1 1/2​

Answer 1

Answer:

First term=a=1

Common difference=d=−4

Second term=t2=a+d=1−4=−3

Third term=t3=a+2d=1+2×−4=1−8=−7

Fourth term=t4=a+3d=1+3×−4=1−12=−11

Fifth term=t5=a+4d=1+4×−4=1−16=−15

Sixth term=t6=a+5d=1+5×−4=1−20=−19

∴, the six terms of A.P are 1,−3,−7,−11,−15,−19

Step-by-step explanation:

hope this helps you!