Write the first six terms of an A.P. in which
1. a=5,d=4
2.a=98, d= -3
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Answer:
Step-by-step explanation:
(1) a=5,d=4
first term =5
second term =a+d
=5+4
=9
third term =a+2d
=5+8
=13
fourth term=x3+d
=13+4
=17
fifth term,=x4+d
=17+4
=21
sixth term =x5+d
=21+4
=25
(2)a=98 d=-3
x2=a+d
=98+(-3)
=96
x3=x2+d
=96+(-3)
=93
x4=x3+d
=93+(-3)
=90
x5=x4+d
=90+(-3)
=87
x6=x5+d
=87+(-3)
=84
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