Question

write the first six terms of AP whose nth term is given by n=3n-2

Answer 1

if tn = 3n-2
then t1 = 3- 2 = 1
t2 = 3*2 - 2 = 4
.........
t6 = 3*6 - 2 = 16

Answer 2

Answer:

here is your answer

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