Question

write the first term , if 2(2x - 7) , 4(x-1) and 5(x-2) are in AP.​

Answer 1

Step-by-step explanation:

Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3