write the first three terms in each of the sequence Defined by the following an=n2+1
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put n = 1 we get:
a1 = 2 X 1 + 1 = 2 + 1 = 3 (First term)
a2 = 2 X 2 + 1 = 4 + 1 = 5 (Second term)
a3 = 2 X 3 + 1 = 6 + 1 = 7 (Third term)
Hence the terms are 3, 5 , 7
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Answer:
Put n=1 we get:
a1 = 2×2+1=2+1=3 (First term)
a2 = 2×2+1=4+1=5 (Second term)
a3=2×3+1=6+1=7 (Third term)
Hence the terms are 3, 5, 7.
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