Question

write the first three terms of arithmetic sequence first term 30 the sum of the first 3 term is 300​

Answer 1

Answer:

The three terms are 30,100,170

Step-by-step explanation:

The first term a is given by 30 , let the common difference be d

Sum of first three terms =300

Sum of n terms of an AP is given by (n÷2)×(2a+(n-1)×d)

In this case n=3 and a=30

(3÷2)×(60+2d)=300

60+2d=200

2d=140

d=70

The second term is 30+70=100

The third term is 100+70=170

Answer 2

Step-by-step explanation:

after (3÷2)×(60+2d)=300 How it comes to 200