Question

write the first three terms of the A.P. whose common difference is 4and the first term is 5 ​

Answer 1

Answer:

Given a=5,d=4

ap=a,a+d,a+2d

ap=5,5+4,5+8

5,9,13,.......

Hope this helps

Answer 2

The first three terms of the Arithmetic Progression is 5 , 9 , 13

Step-by-step explanation:

Given as :

For Arithmetic progression

The common difference = d = 4

The first term = a = 5

Let The first three terms = $t_1$  , $t_2$ , $t_3$

According to question

For n terms of an A.P

$t_n$  = a + (n - 1) d

where a is the first term

And  d is the common difference

Now,

For t = 1

$t_1$  = a + (1 - 1) d

putting the value of a and d

i.e  $t_1$  = 5 + (0) × 4

Or, $t_1$  = 5 + 0

∴   $t_1$  = 5

Again

For t = 2

$t_2$  = a + (2 - 1) d

putting the value of a and d

i.e  $t_2$  = 5 + (1) × 4

Or, $t_2$  = 5 + 4

∴   $t_2$  = 9

Again

For t = 3

$t_3$  = a + (3 - 1) d

putting the value of a and d

i.e  $t_3$  = 5 + (2) × 4

Or, $t_3$  = 5 + 8

∴   $t_3$  = 13

So, The first three terms of the A.P , $t_1$  = 5  , $t_2$  = 9 , $t_3$  = 13

Hence, The first three terms of the Arithmetic Progression is 5 , 9 , 13 Answer