write the first two term of the sequence whose nth term is tn=3n-4
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Tn = 3n - 4
=> a+(n-1)d = - 1 + 3n - 3
=> a + (n-1)d = - 1 + 3(n-1)
Comparing both sides, we get
a= - 1
d = 3
First term = - 1
Second term = 2
=> a+(n-1)d = - 1 + 3n - 3
=> a + (n-1)d = - 1 + 3(n-1)
Comparing both sides, we get
a= - 1
d = 3
First term = - 1
Second term = 2
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