Write the first two terms of AP when a=4 and d=3
Answers
Answered by
0
Answer:
4 and 7
Step-by-step explanation:
a1=a+(n-1)*d
=4+(1-1)*3=4
a2=a+(n-1)*d
=4+(2-1)*3
4+3=7
I think it is helpful for you
Answered by
0
Step-by-step explanation:
when a=4 and d=3
so I st term is A1 which is
A1 = 4
A2 = a+d = 4+3= 7
A3= a+2d = 4+ 2(3)= 4+6= 10
so required AP is 4,7,10
Similar questions