Question

write the first two terms of sequence whose nth terms tn=3n-4

Answer 1

t1=3*1-4=-1, t2=3*2-4=2

Answer 2

tn = 3n - 4

First term,
t1 = 3(1) - 4
t1 = 3-4
t1 = -1

Second term,
t2 = 3(2) - 4
t2 = 6 - 4
t2 = 2

Hope this helps you....:)