Question

write the following as the difference of the square of two consecutive natural numbers 89​

Answer 1

Answer:

45^2 - 44^2 = 89

Step-by-step explanation:

(n+1)^2 - n^2= 89

(n+1+n)(n+1-n) = 89

2n+1 = 89

2n = 88

n = 44

So the two consecutive natural numbers are 44 and 44+1

i.e, 44 and 45

Answer 2

HeRe Is Your Ans ⤵

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Let, two consecutive natural numbers be ( X ) and ( X + 1 )

=> (X)² - (X + 1)² = 89

=> X² - (X² + 1 + 2X) = 89

=> X² - X² - 1 - 2X = 89

=> -1 - 2X = 89

=> -2X = 90

=> X = - 45

Verification :-

=> (45)² - (45 + 1)²

=> 2025 - 1936

=> 89

Hence , two consecutive natural numbers are 45 and 46

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