Question

write the following as the sum of low consecvtive positive number of (19)²​

Answer 1

Answer:

To solve this question, first of all, assume the variables for all three integers. As they are consecutive, so they will have a difference of ‘1’ between them. Finally, we will add them up to get 51 and then calculate the value of the variable to get all three integers.

Complete step-by-step answer:

Let the first number be x. Then as all the three given numbers are consecutive, then the next two numbers will be x + 1 and x + 2. Now, according to the given condition in the question, the three integers add up to 51.

⇒x+x+1+x+2=51

⇒3x+3=51

Taking 3 common, we get,

⇒3(x+1)=51

⇒x+1=513

⇒x+1=17

⇒x=17−1

⇒x=16

So, we have obtained our first number as 16. Then the next numbers are x + 1 and x + 2. Substituting the value of x = 16 in x + 1, we have the second number as 16 + 1 = 17.

Similarly, substituting the value of x = 16 in x + 2, we have the third number as 16 + 2 = 18.

Hence, we have obtained three consecutive numbers as 16, 17 and 18.

So, the correct answer is “Option (d)”.

Note: Another method to solve this is by assuming the variables p – 2, p – 1 and p. Then also, the sum would be 51 and we would get the value of the number as 16, 17 and 18.

⇒p+p−2+p−1=51

⇒3p−3=51

⇒3p=51+3

⇒3p=54

⇒p=543=18

Then,

⇒p−1=18−1=17

⇒p−2=18−2=16

Hence, we have again obtained the numbers as 16, 17 and 18.

Step-by-step explanation:

Hope It Helps

Answer 2

Answer:

GIVEN:

write the following as the sum of low consecvtive positive number of (19)²

to find :

low consecvtive positive number of (19)²

solution:

• Square of 19=361

• 1st consecutive natural no. be = x.

• 2nd consecutive natural number be = x+1

• 361 Sum of two consecutive natural

• numbers

• 361=x+(x+1)

• 361=x+x+1

• 361=2x+1

• 361-1-2x

• 360=2x

• 360/2=x

• 180=x

• Therefore, value of x is 180.

• 1st consecutive natural no.= x =180

• 2nd concetive natural number=x+1

• =180+1=181..