Question

Write the following complex number in the form of A+iB
(-i) (2i)​

Answer 1

Answer:

Answer:

⟹ The complex number is 2+i(0).

As we know that,

⟹ i=√-1

⟹ i²=-1

Given that,

⟹ (-i)(2i)

⟹ -2(i²)

⟹ -2(-1)

⟹ 2+i(0)

So, The complex number is 2+i(0)

Answer 2

Step-by-step explanation:

(-i)(2i)=-2

$i {}^{2}$

since i^2= -1 . then , (-2)×(-1)=2 . here, in a+ib we can only have the real part(a), and complex part(b) is null/0.

so,in a+ib form we have(2)+i (0).