Math, asked by kummarisubbarayudu, 6 hours ago

write the following complex numbers in the form A+iB. (-√3+√-2)(2√3-i)​

Answers

Answered by deepanshujaat785
0

Answer:

(−  

3

+  

−2

)(2  

3

−i)

=(−  

3

+  

2

i)(2  

3

−i) [ Since  

−1

=i]

=(−6+  

2

)+i(  

3

+2  

6

)

This the required a+ib form.

Step-by-step explanation:

Answered by 8202sreejiths
0

Answer:

(2−3i)

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Therefore,

(3+4i)(2−3i)=3+4i2−3i×3−4i3−4i

=(3)2−(4i)2(2−3i)(3−4i)

=9+16(6+12i2)−(9+8)i

=25−6−17i

=25−6+25−17i

Here, A=25−6 and B=25−17

Step-by-step explanation:

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