Question

write the following cube in expand form.. pls help me.

Answer 1

hey ur answer !!!!!!!

Answer 2

Solution:-

${(x - \frac{2y}{3} )}^{3} \\ {x}^{3} - {( \frac{2y}{3} )}^{3} - 3 \times x \times \frac{2y}{3} (x - \frac{2y}{3} ) \\ {x}^{3} - \frac{8}{27} {y}^{3} - 2xy(x - \frac{2y}{3} ) \\ ({x}^{3} - \frac{8}{27} {y}^{3} - 2 {x}^{2} y + \frac{4x {y}^{2} }{3} )ans$


i hope it is helpfull for you...☺☺