Write the following cube in expanded form:
(4x – 3y)^3
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(4x)³ - (3y)³ + 3×(4x)×(-3y)×(4x-3y)
= 64x³ - 27y³ - 144x²y + 108xy²
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Answer:
=(4×)³-(3y)³-3(4×)²(3y)+3(4×)(3y)²
=64׳-144ײy+108×y²-27y³
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