write the following cubes in expanded form a (2x+1)3 b (2a- 3b)3
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Answer:
A/ (2x+1)³=
(a+b)³=a³+b³+3ab+(a+b)
=(2x)³+(1)³+3(2x)(1)+(2x+1)
=8x³+1+6x+(2x+1)
=8x³+1+12x²+6x
=8x³+12x²+6x+1
B/ (2a-3b)³=
(a-b)³=a³-b³-3ab-(a-b)
=(2a)³-(3b)³-3(2a)(3b)-(2a-3b)
=8a³-9b³-18ab-(2a-3b)
= 8a³-9b³-36a²b+54ab²
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