Write the following cubes in expanded from :
I) ( 2x + 1 )³
ii) ( 2a - 3b ) ³
iii) [
![\frac{3}2x + 1 \frac{3}2x + 1](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D2x+%2B+1)
³
iv )
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May be this help you.
formula = x
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