Question

write the following cubes in the expanded form: (3а+ Чb)^3​

Answer 1

${(3a + 4b)}^{3} = ( {3a)}^{3} + (4b) {}^{3} + 3(3a)(4b)(3a + 4b)$

$= 27a {}^{3} + 64b {}^{3} + 36ab(3a + 4b)$