Question

write the following cubes in the expanded form. (x/3+y/7)cube

Answer 1

(x/3+y/7)³=(x/3)³+(y/7)³+3(x/3)(y/7)[(x/3)+(y/7)]
(x/3+y/7)³=x/27+y/343+xy/7[(x/3)+(y/7)]
(x/3+y/7)³=x/27+y/343+x²y/21+xy²/49(ANSWER)
Since (a+b)³=a³+b³+3a²b+3ab²

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