Question

write the following equation in the form ax2+bx+c=0 then write the values of a,b,c for each equation
1)(x-1)2=2x+3
plz solve the equation fast​

Answer 1

Answer :-

In this question, we first need to solve the given equation in such a way that 0 should be RHS. Then, we will compare it with ax² + bx + c = 0 and then we can find the value of a , b and c.

Solving the given equation :-

→ ( x - 1 )² = 2x + 3

→ x² + 1 - 2x = 2x + 3

→ x² + 1 - 2x - ( 2x + 3 ) = 0

→ x² + 1 - 2x - 2x - 3 = 0

→ x² - 4x + 1 - 3 = 0

→ x² - 4x - 2 = 0

Comparing the equation -

→ ax² + bx + c = 0

→ x² - 4x - 2 = 0

So,

• a = 1
• b = -4
• c = -2