Question

Write the following equations in standard form ( + + = 0)

(i) 3y-2x=4

(ii) 4- 3x+5y=0​

Answer 1

Answer:

(i) 3y-2x =4

standard form = ax + b = o

so,

3y-2x-4 =0

(ii) second one is in standard form

Answer 2

Answer:

Step-by-step explanation:

1).$x+y=5$

$2x-3y=4$

multiply eq 1 by 2 then the eq can be written as

$2x+2y=10$

$2x-3y=4$

$(-) (+). (-)$

5y= 6

y =6/5

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$additional$  $information$

Solve by elimination method……

Step-by-step explanation:

Lets see, we have two equations given by you…

3x – 5y – 4 = 0  or 3x -5y = 4 ……………. (1).

9x = 2y + 7 or 9x -2y = 7 ……………………(2).

Now only focusing on eq. numbered 1 and 2 …

3x – 5y = 4…………………………(1)

9x – 2y = 7 ………………………(2)

Multiply eq. (1) by 3, we get….

3 (3x – 5y = 4) or 9x – 15y = 12……………………. (3).

Now we can easily subtract (2) and (3) to get…..

9x – 2y = 7

- 9x – 15y = 12.

- ______________

- +13 y = -5

Or we get 13 y = -5 or y = -5/13.

Now we substitute the value of Y = -5/13 in equation (1) we get the value of x.

3x – 5(-5/13) = 4

3x +25/13 = 4

39x + 25 = 52

Or 39x = 52 – 25

39x = 27

Or x = 27/39 = 9 / 13

So x = 9/13 and y = -5/13