Question

write the following fraction in ascending order 3/7,5/10,7/15,8/9,3/5​

Answer 1

Answer:

The correct sequence of ascending order ( lowest value to highest value ) is :

$\frac{3}{7}$ < $\frac{7}{15}$ < $\frac{5}{10}$ < $\frac{3}{5}$ < $\frac{8}{79}$

step-by-step explanation:

the given fractions are :

$\frac{3}{7}$

$\frac{5}{10}$

$\frac{7}{15}$

$\frac{8}{9}$

$\frac{3}{5}$

Now,

We know that

to arrange any given fractions in ascending or descending order,

we must make the denominator of all the given fractions same.

So,

we have to make the denominator same.

For this,

we have to take L.C.M of all the denominators.

Now,

calculating the L.C.M of 7,10,15,9,5

we get,

L.C.M = 630 ( see the attachment )

Now, as the denominators are same,

i.e. 630

accordingly we have to multiply the numerator with that number which is resultant when 630 is divided by the denominators.

so, further

$\frac{3}{7}$ = $\frac{3×90}{7×90}$= $\frac{270}{630}$

$\frac{5}{10}$= $\frac{5×63}{10×63}$ = $\frac{315}{630}$

$\frac{7}{15}$=$\frac{7×42}{15×42}$=$\frac{294}{630}$

$\frac{8}{9}$=$\frac{8×70}{9×70}$=$\frac{560}{630}$

$\frac{3}{5}$$\frac{3×126}{5×126}$=$\frac{378}{630}$

After comparing the numerators,

we get,

$\frac{270}{630}$ < $\frac{294}{630}$ < $\frac{315}{630}$ < $\frac{378}{630}$ < $\frac{560}{630}$

=> $\frac{3}{7}$ < $\frac{7}{15}$ < $\frac{5}{10}$ < $\frac{3}{5}$ < $\frac{8}{79}$

Answer 2

Answer:

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